AMC 10 · 2021 · #22

Grade 11 algebra
vieta-formulassymmetric-polynomialsdouble-angle-formulatrigonometric-ratios identify-subproblemspattern-recognition ↑ Prerequisites: vieta-formulas
📏 Long solution 💡 3 insights
Problem
A monic cubic has three cosine values as its roots, the angles being multiples of a seventh of a full turn. Find the product of its three coefficients.

Pick an answer.

(A)
${-}\frac{3}{49}$
(B)
${-}\frac{1}{28}$
(C)
$\frac{\sqrt[3]7}{64}$
(D)
$\frac{1}{32}$
(E)
$\frac{1}{28}$
How to solve
Strategy Identify Subproblems

Do not try to find the polynomial as a whole. Vieta's relations say each coefficient is one symmetric combination of the roots, so abc splits into three separate, smaller questions: the sum of the three cosines, the sum of their three pairwise products, and their product. Each of those three is a short trigonometry exercise once the angles are renamed as θ, 2θ, 4θ, because that renaming exposes a doubling pattern that sine identities collapse.

1STEP 1

Split the product into three parts

Write the coefficients as symmetric functions.

a=-(r₁+r₂+r₃), b=r₁r₂+r₁r₃+r₂r₃, c=-r₁r₂r₃, abc=(r₁+r₂+r₃)(r₁r₂+r₁r₃+r₂r₃)(r₁r₂r₃)
2STEP 2

Rename as a doubling ladder

The angles form a doubling ladder.

θ=2π/7; cos 4θ=cos8π/7=cos(2π-8π/7)=cos6π/7
3STEP 3

Find the sum of the roots

Multiplying by a sine makes it telescope.

2sinπ/7cos2kπ/7=sin((2k+1)π)/7-sin((2k-1)π)/7 ⟹ 2sinπ/7 S=sin7π/7-sinπ/7=-sinπ/7 ⟹ S=-1/2, a=1/2
4STEP 4

Find the pairwise sum

Turning products into sums reproduces the earlier value.

cos2π/7cos4π/7+cos2π/7cos6π/7+cos4π/7cos6π/7=1/2(2cos2π/7+2cos4π/7+2cos6π/7)=S=-1/2, b=-1/2
5STEP 5

Find the product of the roots

The sine double-angle formula collapses the product.

sinθcosθcos 2θcos 4θ=1/8sin 8θ=1/8sinθ ⟹ cos2π/7cos4π/7cos6π/7=1/8, c=-1/8
6STEP 6

Multiply the three coefficients

Multiplying gives one thirty-second.

abc=1/2·(-1/2)·(-1/8)=1/32
Answer
1/32
Check the three symmetric quantities numerically. The roots are about 0.6235, -0.2225, and -0.9010. Their sum is about -0.500, matching -1/2. Their pairwise products sum to about -0.139-0.561+0.200=-0.500, matching -1/2. Their product is about 0.1250, matching 1/8. So a=1/2, b=-1/2, c=-1/8 and abc=1/32≈ 0.03125. Two structural checks also fit: exactly two of the coefficients are negative, so abc must be positive, which rules out the two negative choices; and every symmetric function of a full set of conjugate cosines is rational, so a choice containing ∛(7) cannot be right.
💡Key takeaway

You never need the roots themselves: a monic cubic's coefficients are just the roots' sum, pair-sum, and product, and multiplying a chain of cosines by the right sine makes each of those three collapse to a simple fraction.

  • Vieta splits abc into three parts
  • Rename the angles as a doubling ladder
  • Sum of the roots is -1/2
  • Pairwise sum is also -1/2
  • Product of the roots is 1/8
  • Multiply the three coefficients