AMC 10 · 2025 · #3

Grade 8 algebra
mean-median-mode-rangesystems-of-equationslinear-equations-two-var convert-to-algebra ↑ Prerequisites: mean-median-mode-range
📏 Medium solution 💡 2 insights
Problem
A student team and a teacher team together have 15 people. The students average 12 years old; the teachers average 55. If Ash joins the students, their average rises to 14; if Ash instead joins the teachers, their average drops to 52. Find Ash's age.

Pick an answer.

(A)
28
(B)
29
(C)
30
(D)
32
(E)
33
How to solve
Strategy Introduce a Variable

Ash's age and both team sizes are unknown, so Tool #4 (Introduce a Variable) names them A, S, and T and pins down the link S+T=15. Each 'if Ash joins' sentence is a separate average condition, so Tool #7 (Identify Subproblems) turns the two scenarios into two equations, and Tool #13 (Convert to Algebra) rewrites each average statement as a clean equation using total age = average × count. Two equations plus the head-count constraint pin down every unknown.

1STEP 1

Name the unknowns

Let A be Ash's age, S the students, T the teachers, with S+T=15. Keep the sizes separate — Ash shifts each average differently.

S+T=15
2STEP 2

Turn the student scenario into an equation

The S students total 12S. After Ash joins, S+1 people average 14, so 12S+A=14(S+1), which expands to A=2S+14.

12S+A=14(S+1) → A=2S+14
3STEP 3

Turn the teacher scenario into an equation

The T teachers total 55T. After Ash joins, T+1 people average 52, so 55T+A=52(T+1), which expands to A=-3T+52.

55T+A=52(T+1) → A=-3T+52
4STEP 4

Solve the system for the team sizes

Both equal A, so 2S+14=-3T+52, i.e. 2S+3T=38. Substitute S=15-T: 30+T=38, so T=8 and S=7.

2S+3T=38, S=15-T → 30+T=38 → T=8, S=7
5STEP 5

Compute Ash's age

Put S=7 into A=2S+14: A=2(7)+14=28. Check: A=-3(8)+52=28 too, so Ash is 28 — choice (A).

A=2(7)+14=28 → (A)
Answer
28
Ash's age should sit between the two team averages of 12 and 55, and it does — 28 is well inside that range. Check both averages directly: the students become 127+288\frac{12 · 7+28}{8}=1128\frac{112}{8}=14 and the teachers become 558+289\frac{55 · 8+28}{9}=4689\frac{468}{9}=52. Both match, so 28 is consistent with every condition.
💡Key takeaway

Total age is the average times the number of people, so adding one person just adds their age to the total — write that fact as an equation for each team and the sizes fall out.

  • Name the unknowns
  • Turn the student scenario into an equation
  • Turn the teacher scenario into an equation
  • Solve the system for the team sizes
  • Compute Ash's age