AMC 10 · 2025 · #16

Grade 10 geometry-2drate-ratio
trigonometric-ratiosangle-bisector-theoremisosceles-right-triangle dimensional-analysisidentify-subproblems ↑ Prerequisites: rate
📏 Long solution 💡 3 insights
Problem
A clock with an hour hand and a minute hand is set to midnight, left running for exactly 2025 minutes, and then stops. At that instant the two hands form an angle. Find the tangent of the acute angle between them.

Pick an answer.

(A)
0
(B)
$\sqrt{2}-1$
(C)
$2-\sqrt{2}$
(D)
$\frac{\sqrt{2}}{2}$
(E)
$3-\sqrt{2}$
How to solve
Strategy Analyze the Units

The problem hands me a duration in minutes and asks for something about angles, so the whole game is a unit conversion: each hand has its own constant speed in degrees per minute, and once I write those two rates down, every position is just rate times time (Analyze the Units). That splits the work into two clean subproblems (Identify Subproblems): first the size of the angle between the hands, then the tangent of that angle. The second subproblem is where a picture earns its keep (Draw a Diagram) — the angle turns out to be exactly half of 45 degrees, so I can build it by drawing a 45-degree right triangle and bisecting it, instead of recalling a trigonometric identity.

1STEP 1

Convert 2025 minutes to a clock reading

2025 minutes reads 9:45.

2025 = 60 × 33 + 45, 33 = 12 × 2 + 9
2STEP 2

Place the minute hand

The minute hand sits at 270 degrees.

360°/60 × 45 = 6° × 45 = 270°
3STEP 3

Place the hour hand

The hour hand has crept to 292.5 degrees.

9 × 30° + 45 × 0.5° = 270° + 22.5° = 292.5°
4STEP 4

Subtract to get the acute angle

The gap is the acute 22.5 degrees.

θ = 292.5° - 270° = 22.5°, 22.5° < 90°
5STEP 5

Bisect a 45-degree right triangle

Bisect a 45 degree right triangle.

AP/PB = OA/OB = 1/√(2), AP + PB = 1 → AP = 1/(1+√(2)) = √(2)-1
6STEP 6

Read the tangent off the picture

Reading it off gives root two minus one.

tan 22.5° = AP/OA = (√(2)-1)/1 = √(2)-1
Answer
√(2)-1
The angle 22.5 degrees lies between 0 and 45, so its tangent must sit strictly between 0 and 1, and it must also be smaller than tan 30°, which is about 0.577. The value √(2)-1 is about 0.414 and passes both tests; a calculator gives tan 22.5° = 0.41421…, matching. Every other choice fails: (A) 0 would mean the hands overlap, but they are 22.5 degrees apart; (C) 2-√(2) ≈ 0.586, (D) √(2)/2 ≈ 0.707, and (E) 3-√(2) ≈ 1.586 are all too big for an angle under 30 degrees. The clock reading also survives a separate check: 2025 minutes is one full day plus 9 hours 45 minutes, so the clock stops at 9:45 the next morning, and a 12-hour dial shows the same picture then as at 9:45 at night.
💡Key takeaway

Give each hand its own speed in degrees per minute, subtract the two positions to get the gap, then find the tangent of that gap by bisecting a 45-degree right triangle.

  • Convert 2025 minutes to a clock reading
  • Place the minute hand
  • Place the hour hand
  • Subtract to get the acute angle
  • Bisect a 45-degree right triangle
  • Read the tangent off the picture