AMC 8 · 2001 · #11
Grade 6 geometry-2d
Pick an answer.
AMC 8 2001 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Coordinates always invite Tool #1 (Draw a Diagram): plot the four points on grid paper and the quadrilateral's shape becomes obvious. Once we can see it, the slanted side DA is the only awkward feature, so we reach for Tool #7 (Identify Subproblems): cut the quadrilateral along the x-axis into a rectangle (below) and a right triangle (above). Both have horizontal and vertical sides, so each area is one easy Grade 6 formula. Add the two pieces. We deliberately skip Tool #13 (algebra/coordinate formulas like the Shoelace formula) because decomposition is faster and uses only elementary area formulas.
Plot the four points and join them A → B → C → D → A: only side DA is slanted, so ABCD comes out as a trapezoid.
Plotting ordered pairs in the coordinate plane and reading off the resulting figure is the core Grade 5 coordinate-graphing skill.
5.G.A.2Draw A DiagramCut along the x-axis: it runs through D(-3,0) and (3,0) on side DA, splitting ABCD into a rectangle below and a right triangle above.
Decomposing a polygon into rectangles and right triangles is exactly the Grade 6 "find area by composing/decomposing" technique.
6.G.A.1Identify SubproblemsRectangle area: width 6 (x=-3 to x=3) times height 2 (y=-2 to y=0) gives 12.
Width × height for a rectangle is the Grade 4 area formula.
4.MD.A.3Identify SubproblemsRight triangle area: half of base 6 ((-3,0) to (3,0)) times height 2 (up to (3,2)) gives 6.
Half of base times height for a right triangle is the standard Grade 6 area rule.
6.G.A.1Identify SubproblemsThe two pieces meet only along the cut and never overlap, so add them for 18.
Area is additive over non-overlapping pieces — the heart of the decomposition standard.
6.G.A.1Identify SubproblemsPlot the points, then slice the shape into a rectangle and a right triangle — both areas are Grade 6 formulas, and their sum is the answer.