AMC 8 · 2001 · #20
Grade 6 logicPick an answer.
AMC 8 2001 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Each speaker compares only two numbers: their own score and Kaleana's score K. So every statement has to be forced by that single comparison. Tool #3 (Eliminate Possibilities) is the right lead: for each of Quay, Marty, and Shana, list the three possibilities ( > K, = K, < K) and eliminate the ones that don't make the statement certain. Tool #2 (Make a Systematic List) is the bookkeeping that keeps the three cases straight without overlooking one. We avoid Tool #13 (Algebra) because the whole problem is settled by three short comparisons — no equations needed.
Quay sees only his own score and Kaleana's, so the one match he can guarantee is Q = K.
Quay can't peek at Marty's or Shana's scores, so a guaranteed match must be between his score and Kaleana's.
6.EE.B.5Eliminate PossibilitiesMarty sees only M and K, and "not the lowest" is guaranteed by that single comparison only when M > K.
"Not the lowest" is a guarantee only if Marty already beats the one score he can see — Kaleana's.
6.EE.B.8Eliminate PossibilitiesBy the mirror argument, Shana's "not the highest" is guaranteed only when S < K.
"Not the highest" is a guarantee only if Shana already loses to the one score she can see.
6.EE.B.8Eliminate PossibilitiesSubstitute K = Q into the three inequalities and they line up as S < Q < M.
Three short inequalities about the same anchor K line up into one ordering from smallest to largest.
6.EE.B.8Make A Systematic ListLowest to highest is S, Q, M, which matches choice (A).
Only choice (A) lists the three names in the order S, Q, M.
6.EE.B.5Eliminate PossibilitiesEach speaker can only compare their score to Kaleana's. So every thought has to be guaranteed by that one comparison. Quay's "tie" forces Q = K, Marty's "not lowest" forces M > K, and Shana's "not highest" forces S < K — chained together, S < Q < M, answer (A).