AMC 8 · 2002 · #11
Grade 4 geometry-2dcounting
Pick an answer.
AMC 8 2002 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The picture already gives the first three cases for free, which is the cue for Tool #5 (Look for a Pattern): count the tiles in those small squares and see what rule governs them. Tool #9 (Solve an Easier Related Problem) is what makes Tool #5 honest — we trust the pattern only after verifying it on the n=1, 2, 3 cases we can see and count. Once the rule "n-th square has n² tiles" is locked in, the 6th and 7th squares come from one subtraction. No algebra needed.
Count the tiles in the drawn squares — they hold 1, 4, 9 tiles.
Counting unit tiles in an n-by-n square is exactly the Grade 3 area-by-tiling idea: side × side.
3.MD.C.7Solve An Easier Related ProblemThe counts 1, 4, 9 are 1², 2², 3², so the n-th square uses n² tiles.
Three matching cases plus a confirmed fourth is enough to trust the rule — that is the Grade 4 "generate and analyze a pattern" move.
4.OA.C.5Look For A PatternApply n²: the 6th square has 36 tiles, the 7th has 49.
Same area-as-tile-count picture, just bigger sides.
3.MD.C.7Look For A PatternSubtract: 49 - 36 = 13 more tiles, so (C).
The question asks "how many more," which is a Grade 3 take-away comparison.
3.OA.D.8Look For A PatternCount the small cases (1, 4, 9), spot the square-number rule, then subtract: 7² - 6² = 49 - 36 = 13. Answer (C).