AMC 8 · 2003 · #8
Grade 6 geometry-2d
Pick an answer.
AMC 8 2003 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The figures are already drawn for us, so Tool #1 (Draw a Diagram) just means reading each shape and computing its top area with the right formula. Tool #11 (Find an Invariant) is the key idea: because every friend uses the same amount of dough and the same thickness, the total top area per friend is the same constant. That means the number of cookies is inversely proportional to one cookie's area — the friend with the biggest cookie ends up with the fewest cookies. So the question "who makes the fewest" becomes "who has the largest single-cookie area."
Art's trapezoid: average the parallel sides , times height 3 = 12 in².
Grade 6 area of a trapezoid: average the two parallel sides, then multiply by the height.
6.G.A.1Draw A DiagramRoger's rectangle: 4 × 2 = 8 in².
Grade 6 area of a rectangle: length times width.
6.G.A.1Draw A DiagramPaul's parallelogram: base 3 × perpendicular height 2 = 6 in².
Grade 6 area of a parallelogram: base times perpendicular height.
6.G.A.1Draw A DiagramTrisha's right triangle: the legs are base and height, so × 3 × 4 = 6 in².
Grade 6 area of a right triangle: half of base times height.
6.G.A.1Draw A DiagramSame total area, so fewer cookies means a bigger cookie: 12 > 8 > 6 = 6, so the largest cookie makes the fewest.
Constant total area split into cookies of size a gives count = . Bigger a means smaller count.
6.RP.A.3Work BackwardsWhen everyone uses the same amount of dough at the same thickness, fewer cookies means each one is bigger. Compute each shape's area with the Grade 6 polygon formulas, and the friend with the largest cookie is the one who bakes the fewest.