AMC 8 · 2004 · #10
Grade 5 arithmeticPick an answer.
AMC 8 2004 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The four shifts come in four different formats — a mixed number of hours, a count of minutes, a clock-time range, and the phrase "a half-hour." Tool #7 (Break into Subproblems) handles each shift on its own: convert it to a common unit, then move on. Tool #2 (Make a List or Table) keeps the four numbers lined up so nothing gets dropped before the final sum. Once the total time is in hand, multiplying by $3 per hour is one short step.
Monday: hours = × 60 = 75 min.
A quarter of 60 is 15, so five quarters is 5 × 15 = 75. The Grade 5 mixed-number multiplication move.
5.NF.B.6Identify SubproblemsTuesday is already 50 min — no conversion needed.
Recognizing that one shift is already in the target unit is part of the Grade 4 unit-conversion habit: only convert what needs converting.
4.MD.A.1Identify SubproblemsWednesday: 8{:}20 to 10{:}45 is 2 h 25 min = 145 min.
Counting up from the start time is the Grade 4 elapsed-time strategy: jump full hours first, then add the leftover minutes.
4.MD.A.2Identify SubproblemsFriday: half an hour = × 60 = 30 min.
Half of an hour is the most familiar fraction-of-a-quantity in everyday talk; it lands at 30 min.
5.NF.B.6Identify SubproblemsAdd the four shifts: 75 + 50 + 145 + 30 = 300 min = 5 h, then × $3 gives (E).
Stacking the four numbers in a small table makes the column-add automatic. Dividing 300 by 60 converts back to hours, then the Grade 4 "multiply to find total cost" step finishes the problem.
4.MD.A.2Make A Systematic ListWhen a problem mixes hours, minutes, and clock times, convert every shift to one unit first — then a single addition and one multiplication finish the job.