AMC 8 · 2005 · #13
Grade 3 geometry-2d
Pick an answer.
AMC 8 2005 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Tool #1 (Draw a Diagram) is the cracker: sketch the L-shape with the labels, then extend AF down and DC up until they meet at a new corner O. The L is now the big rectangle ABCO with a smaller rectangle cut out of one corner — and that cut-out rectangle has sides DE and EF. Tool #7 (Identify Subproblems) then breaks the question into two small pieces: (a) use the right-angle structure to find DE from the vertical sides, and (b) use the area equation "big rectangle minus cut-out = 52" to find EF. Choosing Tool #1 + Tool #7 over Tool #13 (Convert to Algebra) keeps the work at one short subtraction and one short equation — no system of equations needed.
Extend FA down and DC up to a new corner O, forming rectangle ABCO — the L is that big rectangle minus a small cut-out corner FEDO.
Closing the L into a rectangle turns an unfamiliar 6-sided shape into a difference of two rectangles — shapes whose area is just length times width.
3.G.A.1Draw A DiagramOn the left, FA stacked on DE must span the full height BC, so FA + DE = BC gives DE = 4.
In any axis-aligned shape, the verticals on the left must sum to the same total as the verticals on the right — that is just "two paths between the same two horizontals have equal length."
3.MD.D.8Identify SubproblemsThe L's area is the big rectangle minus the DE-by-EF cut-out, so 72 − 4 × EF = 52 gives EF = 5.
"Big rectangle minus small rectangle" is the cleanest way to handle any L-shape area.
3.MD.C.7Identify SubproblemsAdd the two subproblem answers for the requested sum: DE + EF = 4 + 5.
Combine the two subproblem answers — the last step of any split-it-up plan.
3.OA.D.8Identify SubproblemsClose the L-shape into a full rectangle, and the missing corner is a smaller rectangle. "Big rectangle minus cut-out = 52" gives EF, and "left verticals add up to the right vertical" gives DE — pure Grade 3 area arithmetic.