AMC 8 · 2008 · #4
Grade 3 geometry-2d
Pick an answer.
AMC 8 2008 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The outer triangle is built from two kinds of pieces: one small triangle plus three trapezoids, with nothing overlapping. Tool #7 (Identify Subproblems) breaks the goal into two easy steps — first find the total area taken by all three trapezoids (subtract the inner triangle from the outer), then split that area evenly among the three congruent trapezoids. Tool #15 (Visualize) confirms the picture: the three trapezoids tile the ring-shaped region between the triangles with no gaps and no overlap, so their areas truly add up to the difference.
The outer triangle is the inner triangle plus three non-overlapping trapezoids, so its area is the sum of those parts.
Grade 3 area work: when a region is split into non-overlapping pieces, the whole area equals the sum of the parts.
3.MD.C.7Organize Information In More WaysSubtract the inner triangle from the outer triangle to get the three trapezoids' combined area, 15.
This is the "area of the ring" subproblem: the trapezoids fill exactly the space the small triangle doesn't.
3.MD.C.7Identify SubproblemsThe three trapezoids are congruent, so split that combined area equally by dividing it by 3.
Grade 3 partitive division: 15 shared equally among 3 identical pieces gives 5 each.
3.OA.A.2Identify SubproblemsBig triangle minus small triangle gives the trapezoids' combined area — then divide by 3 because they are identical. Subtract, then share equally.