AMC 8 · 2006 · #21
Grade 5 geometry-3dPick an answer.
AMC 8 2006 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The story is physical: a rock goes in, the water has nowhere to go but up. Tool #10 (Create a Physical Representation) makes the key insight concrete — picture the rock sliding in and shoving an equal volume of water upward. That displaced water spreads across the same rectangular base, forming a thin slab whose volume equals the rock's volume. Tool #7 (Identify Subproblems) splits the work into two clean pieces: (i) compute the base area, (ii) divide the rock's volume by that area to get the slab's thickness, which is the rise. The given numbers 37 cm and 50 cm are deliberately included to confirm the rock fits and the water does not overflow — they do not enter the calculation.
Find the base area — the aquarium's 4000 cm² rectangle stays the same at every water level.
Multiplying length by width for a rectangle is the Grade 5 multi-digit multiplication move — and the base area stays the same as the water level changes.
5.NBT.B.5Identify SubproblemsThe submerged rock shoves up its own volume of water as a thin slab, so the slab's volume is 1000 cm³.
Think of the rock as silently swapping places with water: where rock now sits, water used to sit, and that water has to go somewhere — up.
5.MD.C.5Create A Physical RepresentationApply the rectangular-prism rule to the slab: volume = base area × thickness, where the thickness is the rise h.
Any thin slab with a rectangular base has volume "area times thickness" — the same Grade 5 volume formula as for a full rectangular prism.
5.MD.C.5Create A Physical RepresentationDivide both sides by 4000 to get the rise: h = = 0.25 cm, choice (A).
Dividing 1000 by 4000 and writing the result as the decimal 0.25 is Grade 5 decimal arithmetic — a quarter of a centimeter rise.
5.NBT.B.7Identify SubproblemsA submerged rock pushes up its own volume of water, which spreads across the aquarium's base as a thin slab — divide the rock's volume by the base area and you have the rise.