AMC 8 · 2009 · #1
Grade 4 arithmeticPick an answer.
AMC 8 2009 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
We know the final amount (4 apples kept) and the operations that led to it (gave half away, then gave 3 more). Tool #11 (Work Backwards) is built for exactly this shape: start at the end and undo each step. Tool #7 (Identify Subproblems) helps name the two stages cleanly — "after Ann" and "after Cassie" — so each reversal is a single, simple operation.
Name two stages: T = the original total, A = what's left after Ann's half, giving the chain T → A → 4.
Splitting the chain of events into named stages is the Tool #7 (subproblems) move — each arrow becomes one small undo step.
4.OA.A.3Identify SubproblemsUndo the last event: before giving Cassie 3, Bridget had 4 + 3 = 7 apples — that is A.
Reversing a "gave away 3" event with a +3 addition is the first step of a two-step word problem.
3.OA.D.8Work BackwardsA = 7 is only half the original, so double it: T = 2 × 7 = 14 → (E).
Undoing "take half" is the same as multiplying by 2 — a Grade 3 multiplication-within-100 idea.
3.OA.A.3Work BackwardsThis AMC 8 problem only needs Grade 4 "work backwards" reasoning — undo each step from the end — that you already know!