AMC 8 · 2011 · #2
Grade 4 geometry-2dPick an answer.
AMC 8 2011 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The question bundles three small jobs into one sentence: find Karl's area, find Makenna's area, then compare. Tool #7 (Identify Subproblems) makes that structure explicit — solve each rectangle separately, then subtract. Tool #8 (Analyze the Units) is a quick sanity check that ft × ft = ft², so the answer's unit "square feet" lines up automatically and we don't need to convert anything.
Multiply Karl's sides with A = length × width: 20 × 45 gives 900 square feet.
Multiplying side lengths to get area is the Grade 3 rectangle-area standard.
3.MD.C.7Identify SubproblemsMultiply Makenna's sides the same way: 25 × 40 gives 1000 square feet.
Same area formula, just plugged into Makenna's rectangle — Tool #7's second subproblem.
3.MD.C.7Identify SubproblemsCompare the two areas: 1000 > 900, so Makenna's garden is the larger one.
Comparing multi-digit whole numbers is a Grade 4 place-value skill.
4.NBT.A.2Identify SubproblemsSubtract the areas to size the gap: 1000 - 900 = 100 square feet → (E).
Whole-number subtraction with the unit "square feet" carried along — Grade 4 standard algorithm.
4.NBT.B.4Analyze The UnitsThis AMC 8 problem only needs the Grade 3 "area = length × width" rule plus Grade 4 subtraction — find each area, then take the difference.