AMC 8 · 2012 · #3
Grade 4 arithmeticPick an answer.
AMC 8 2012 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Sunset = sunrise + daylight is a single sum, but it is cleaner to split it into two subproblems (Tool #7): add the hours, then add the minutes, then carry. After computing, Tool #3 (Eliminate Possibilities) lets us check the answer against the five choices — a free verification on any AMC multiple-choice problem. Tool #8 (Units) is implicitly used, but the bookkeeping here is hours vs. minutes, not a unit conversion across systems, so #7 captures the structure best.
Daylight runs from sunrise to sunset, so the correct sunset equals sunrise plus the daylight length; ignore the misprinted one.
Picking the right relationship before computing is the first move of Tool #7 — name the subproblems before doing them.
4.MD.A.2Identify SubproblemsAdd the hours: 6 (from 6{:}57) plus 10 hours of daylight gives 16 hours.
Treating hours as their own column is exactly the "add place by place" Grade 4 algorithm.
4.NBT.B.4Identify SubproblemsAdd the minutes: 57 plus 24 gives 81 minutes.
Same place-value addition, this time in the minutes column.
4.NBT.B.4Identify Subproblems81 minutes tops 60, so trade 60 for 1 hour: 21 minutes are left and the hours climb to 17, giving 17 h 21 min.
Trading 60 minutes for 1 hour is the same idea as carrying 10 ones into a ten — Grade 4 unit conversion within the time system.
4.MD.A.1Identify SubproblemsSubtract 12 from the hours: 17{:}21 becomes 5{:}21 PM, which is choice (B).
Matching the computed result against the five choices is Tool #3 (Eliminate Possibilities) — only (B) survives, the rest are off by 11, 20, 36, or 42 minutes.
4.MD.A.2Eliminate PossibilitiesIf you can add hours, add minutes, and carry 60 minutes as 1 hour, you have all the Grade 4 skills this AMC 8 problem needs.