AMC 8 · 2013 · #4
Grade 5 arithmeticalgebraPick an answer.
AMC 8 2013 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The bill is hidden behind two layers, so Tool #7 (Identify Subproblems) splits the work cleanly. Subproblem A: the 7 extra payments of 2.50 together fill in Judi's one missing share, so we can find one person's share. Subproblem B: once we know one share, the total bill is just 8 shares. Tool #6 (Guess and Check) is a good backup: with only five answer choices, we can divide each by 8 and see which one makes Judi's share equal 7 ×2.50 = $17.50.
Subproblem A: the 7 friends' 2.50 = $17.50.
Equal-groups multiplication: 7 groups of $2.50 — a Grade 3 multiplication word-problem idea.
3.OA.A.3Identify SubproblemsEvery share is equal, so each person's share is also $17.50.
"Equal shares" means we can use Judi's share as the size of any share.
3.OA.A.3Identify SubproblemsSubproblem B: the bill is 8 equal shares, so multiply one share by 8 to get $140.
Breaking 17.50 into 17 + 0.5 keeps the decimal multiplication friendly — Grade 5 decimals.
5.NBT.B.7Identify SubproblemsThe total $140 matches answer choice (C).
Final value matches choice (C).
5.NBT.B.7Identify SubproblemsOnce you see that the 7 extra payments add up to exactly Judi's one share, the rest is just Grade 5 decimal multiplication: 8 shares of 140.