AMC 8 · 2015 · #8

Grade 6 geometry-2d
perimeterinterval-arithmetic bound-inequality-then-enumerate ↑ Prerequisites: multi-digit-arithmetic
📏 Short solution 💡 3 insights
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Problem
A triangle has two sides of length 5 and 19. The third side can be any length that still forms a real triangle. Find the smallest whole number that is strictly greater than the perimeter, no matter which valid third side is chosen.

Pick an answer.

(A)
24
(B)
29
(C)
43
(D)
48
(E)
57

AMC 8 2015 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.

How to solve
Strategy Draw a Diagram

The hidden gate is figuring out which values of x are even allowed. Tool #1 (Draw a Diagram) shows it directly: lay the side of length 19 flat, then swing the side of length 5. The far tip can reach at most 19 + 5 = 24 (when both are stretched in the same direction) and at least 19 - 5 = 14 (when folded back), so x must satisfy 14 < x < 24 — those are the limits where the triangle flattens into a line. Tool #9 (Solve an Easier Related Problem) confirms the same rule with a friendly case (sides 3 and 4 allow 1 < x < 7). Once we know x < 24, the perimeter P = 24 + x < 48, and Tool #6 (Guess and Check) on the choices picks the smallest whole number that stays above every legal P.

1STEP 1

Sketch it: lay the 19-side flat, attach the 5-side at one end, and swing it like a clock hand — the third side x closes the gap.

2STEP 2

As the 5-side swings, x nears 24 or 14 but never reaches either — at those limits the three sides collapse into a straight line.

14 < x < 24
3STEP 3

Test the rule on sides 3 and 4: the same swing gives 1 < x < 7, and x = 7 makes 3 + 4 = 7 collapse to a line — confirmed.

sides 3, 4 → 1 < x < 7
4STEP 4

The perimeter is P = 24 + x, and since x < 24 it stays strictly below 48 — reaching, say, 47.99 but never 48 itself.

P = 5 + 19 + x = 24 + x < 24 + 24 = 48
5STEP 5

Pick the smallest whole number above every perimeter: 47 fails (P could be 47.5), but 48 always beats P < 48 — so the answer is 48 (D).

P < 48 → smallest whole number > P is 48 → (D)
Answer
48
Sanity-test the bound. Pick a legal x, say x = 20: the sides 5, 19, 20 satisfy 5 + 19 = 24 > 20, so it is a real triangle, and P = 44 < 48. Push x toward the limit: x = 23.9 gives P = 47.9 < 48. Push past: x = 24 gives sides 5, 19, 24 with 5 + 19 = 24 (collapsed line, not a triangle). The cutoff sits exactly at 48, confirming the answer (D).
💡Key takeaway

This AMC 8 problem only needs Grade 6 inequality reasoning — once you see why the third side has to stay under 5 + 19 = 24, the perimeter cap of 48 falls right out!