Competition · AMC preparation · step 4 of 4
AMC 8 · 2018 · #2
Grade 5 arithmeticpatternPick an answer.
AMC 8 2018 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
Each factor 1 + 1/k rewrites cleanly as (k+1)/k, so the product becomes 2/1·3/2·4/3…7/6 — a chain where each numerator matches the next denominator. Tool #5 (Look for a Pattern) is exactly the move that spots this telescoping cancellation, turning a six-fraction multiplication into a one-step answer. Tool #9 (Easier Problem) backs it up: trying the same product with only 2 or 3 factors first reveals the rule "the answer is just the last numerator" before we trust it on all six.
Rewrite each factor as a fraction
Rewrite each factor 1 + as , so the six factors become , , , , , .
Adding a whole number and a unit fraction with the same denominator is just combining unit fractions — a Grade 4 fraction skill.
4.NF.B.3Look For A PatternTry smaller cases first
Test smaller cases (Tool #9): 2 factors give 3, 3 give 4, 4 give 5 — the pattern leaves only the last numerator.
Generating a pattern from a few simple cases and stating its rule is the Grade 4 "shape/number pattern" standard.
4.OA.C.5Solve An Easier Related ProblemCancel across the product
Apply the telescoping cancellation to all six factors: every inner number cancels, leaving ····· = .
Multiplying fractions and cancelling common factors top-and-bottom is exactly the Grade 5 fraction-by-fraction multiplication standard.
Multiplying the six fractions 2/1·3/2·4/3·5/4·6/5·7/6 cancels every repeated number and leaves only the first bottom and the last top, 7/1.
▸ Why?
Multiplying the fractions multiplies all six tops into one product and all six bottoms into another, so the whole thing becomes the single fraction (2·3·4·5·6·7)/(1·2·3·4·5·6).
▸ Why?
In that single fraction the top is the block 2·3·4·5·6 times 7, and the bottom is the same block 2·3·4·5·6 times 1, so top and bottom share the whole block 2·3·4·5·6 as a common factor.
▸ Why?
Numbers being multiplied can be regrouped without changing the product, so the top 2·3·4·5·6·7 can be read as the single block (2·3·4·5·6) multiplied by 7.
▸ Why?
The bottom's leading 1 contributes nothing to a product, so 1·2·3·4·5·6 is just the block 2·3·4·5·6 itself.
▸ Why?
Dividing both the top and the bottom by that shared block 2·3·4·5·6 removes it and leaves 7 on top and 1 on the bottom, and dividing a fraction's top and bottom by the same nonzero number never changes its value.
Read off the value
Read off the value: = 7, which matches choice (D).
A fraction with denominator 1 is just the numerator — a Grade 4 fraction-meaning idea.
4.NF.B.3Look For A PatternThis AMC 8 problem only needs Grade 5 fraction multiplication you already know — once you spot the cancellation pattern, the answer falls out in one line!
- Rewrite each factor as a fraction
- Try smaller cases first
- Cancel across the product
- Read off the value
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