AMC 8 · 2018 · #6
Grade 4 rate-ratioPick an answer.
AMC 8 2018 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
This is a classic rate problem (distance, speed, time). Tool #8 (Analyze the Units) keeps the bookkeeping honest: miles/(minutes-per-mile) = minutes, so working with the rate "minutes per mile" lets us avoid converting to mph at all. Tool #9 (Easier Related Problem) is the elegance move: instead of computing the highway speed, first ask the smaller question "how long would 10 highway miles take?" — that gives a per-mile rate we can scale up by 5 to reach the actual 50 miles. Tool #7 (Identify Subproblems) splits the trip into the highway leg and the coastal leg, which are summed at the very end. This avoids reaching for Tool #13 (Algebra) when scaling and addition are enough.
Flip "3 times as fast" into per-mile time: each highway mile takes the time of a coastal mile.
"3 times as fast" is a Grade 4 multiplicative comparison — and the speed/time inverse just flips the multiplier.
4.OA.A.1Analyze The UnitsSolve the easier case first: 10 highway miles take of the coastal 30 minutes, or 10 minutes.
Multiplying a whole number by the fraction is exactly the Grade 4 "fraction times a whole number" standard.
4.NF.B.4Solve An Easier Related ProblemScale up: 50 highway miles is 5 times 10 miles at the same speed, so 5 × 10 = 50 minutes.
Scaling time by the same factor as distance (at constant speed) is the Grade 4 distance-time word-problem move.
4.MD.A.2Analyze The UnitsAdd the legs: highway 50 minutes plus coastal 30 minutes gives 80 minutes total.
Combining two sub-trip times into one total trip time is the addition piece of a multi-step distance-time word problem.
4.MD.A.2Identify SubproblemsThis AMC 8 problem only needs Grade 4 multiplicative comparison ("3 times as fast means the time") that you already know!