AMC 8 · 2020 · #5
Grade 4 rate-ratioPick an answer.
AMC 8 2020 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The question hides two clean subproblems: (1) what percent of the pitcher is actually juice, and (2) once that juice is split into 5 equal parts, how big is one part? Tool #7 (Identify Subproblems) names these two sub-questions and solves them one at a time. Because this is multiple choice, Tool #3 (Eliminate Possibilities) gives us a fast cross-check: 5 times the correct answer must equal the total juice percent (75%), so only one choice survives.
Rewrite the juice fraction with denominator 100 (times 25 top and bottom) to get .
Rewriting a fraction with an equivalent denominator is the Grade 4 fraction-equivalence move ( = ).
4.NF.A.1Identify SubproblemsRead as a percent — it means per hundred — so the pitcher holds 75% of its capacity in juice.
Reading a fraction with denominator 100 as a percent is the Grade 4 decimal/percent notation skill.
4.NF.C.6Identify SubproblemsShare that 75% equally among the 5 cups: 75 ÷ 5 = 15% per cup.
Dividing 75 by 5 within 100 is a Grade 3 fluency fact (5 × 15 = 75).
3.OA.C.7Identify SubproblemsCheck by elimination: 15 × 5 = 75 matches the total juice, so only (C) survives.
Testing each choice against the constraint "5 cups must add back to 75%" is a Grade 3 multiplication fluency check.
3.OA.C.7Eliminate PossibilitiesThis AMC 8 problem only needs Grade 4 fraction-to-percent thinking ( = = 75%) plus a Grade 3 division fact you already know!