AMC 8 · 2024 · #23
Grade 6 rate-ratio
Pick an answer.
AMC 8 2024 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The numbers 2000, 3000, 5000, 8000 are far too big to count cells one by one, so the natural first move is Tool #9 — shrink the problem to small endpoints (0,0)→(Δ x, Δ y), then use Tool #1 to actually draw each tiny segment on graph paper and collect the cell counts in a small table. Tool #5 (Look for a Pattern) then turns the table into a rule of the form "cells = Δ x + Δ y - (correction)", and the correction turns out to depend on how many lattice points the segment passes through. Finally we apply the rule to the original Δ x, Δ y. This stays in the elementary toolkit — no need for Tool #13 (Algebra) or a memorized formula.
Slide the whole picture left 2000 and down 3000 so the segment becomes (0,0)→(3000, 5000); the cell count is unchanged.
Computing 5000-2000 and 8000-3000 is exactly Grade 4 fluent multi-digit subtraction.
4.NBT.B.4Draw A DiagramDraw tiny segments from (0,0) and count: (1,1):1, (1,2):2, (2,3):4, (2,4):4, (3,5):7 cells.
Plotting points and a segment on the coordinate plane and counting cells underneath is exactly the Grade 5 coordinate-plane standard.
5.G.A.2Solve An Easier Related ProblemGuess cells = Δx + Δy - 1: fits (1,2),(2,3),(3,5) but (2,4) gives 5 not 4 and (2,2) gives 3 not 2 — the guess overshoots.
Tabulating cases, proposing a rule, and noticing exactly where it breaks is the Grade 4 "generate a pattern following a rule" activity.
4.OA.C.5Look For A PatternWhere the segment hits an interior lattice point like (1,2) it crosses both grid lines at once, so subtract one more: cells = Δx + Δy - g.
Reading the coordinates of interior lattice points on a plotted segment is exactly Grade 5 coordinate-plane work.
5.G.A.2Draw A DiagramThe lattice points on the segment number gcd(Δx, Δy), so g is exactly that gcd: N = Δx + Δy - gcd(Δx, Δy), matching every small case.
Recognizing the "largest common divisor" of two numbers as the count of lattice steps is exactly the Grade 6 GCD standard.
6.NS.B.4Look For A Patterngcd(3000, 5000) = 1000 since both are 1000 times coprime 3 and 5, so N = 3000 + 5000 - 1000 = 7000 — choice (C).
Finding gcd(3000,5000)=1000 by factoring out the common 1000 is a direct Grade 6 GCD computation.
6.NS.B.4Look For A PatternThis AMC 8 problem only needs Grade 6 greatest common factor (GCD) you already know!