AMC 8 · 2025 · #2
Grade 4 arithmeticPick an answer.
AMC 8 2025 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The cleanest path is Tool #2 (Systematic List): walk through the four distinct symbol types from largest value to smallest, tally how many of each appear, and multiply count × value. Because the Egyptian system is additive, the answer is just the sum of these four products — no place-value juggling needed. Tool #3 (Eliminate Possibilities) is a great second pass for multiple-choice: the absence of the lotus flower (1,000) forces the thousands digit to be 0, which alone narrows the five choices down to (B) 10,423, giving us an independent check on our computation.
Sort the symbols by value, largest first, and count how many of each appear so no group is missed or double-counted.
Sorting objects into the right buckets and counting each bucket is a Kindergarten classify-and-count move.
K.MD.B.3Make A Systematic ListMultiply each count by its symbol's value — a single digit times a power of ten, so just attach the matching number of zeros.
Multiplying a one-digit number by 10, 100, or 10,000 is the Grade 3 "multiples of 10" pattern — just attach the zeros.
3.NBT.A.3Make A Systematic ListAdd the four partial values — no two share a place, so there are no carries and the total is 10,423.
Fluently adding multi-digit whole numbers up to the ten-thousands place is a Grade 4 standard.
4.NBT.B.4Make A Systematic ListCross-check by elimination — the bent finger means at least 10,000 and no lotus flower forces a 0 in the thousands place, so only (B) fits.
Reading a five-digit number and comparing it to the choices uses Grade 4 multi-digit place-value understanding.
4.NBT.A.2Eliminate PossibilitiesThis AMC 8 problem only needs Grade 4 place value and multi-digit addition you already know!