AMC 8 · 2001 · #15
Grade 6 rate-ratioalgebraPick an answer.
AMC 8 2001 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
The story has two distinct phases — Homer alone for the first 4 minutes, then Homer and Christen together. Tool #7 (Identify Subproblems) splits the work along that natural seam: (a) count what Homer peeled alone and subtract from 44 to get what is left, then (b) work out how long the two of them need to finish that remainder, and finally read off Christen's share. Tool #8 (Analyze the Units) keeps every step honest: every multiplication is potatoes/minute × minutes = potatoes, and the rate-addition step pools 3 + 5 correctly because both rates share the same unit.
Count Homer's solo work: 3 per minute for his 4 minutes gives 12 potatoes.
Rate × time = amount. The minute units cancel, leaving potatoes — exactly what we want to count.
5.NBT.B.5Analyze The UnitsSubtract from the pile: 44 minus 12 leaves 32 potatoes for the joint phase.
Total minus what is done leaves what is left — the bridge between phase 1 and phase 2.
4.OA.A.3Identify SubproblemsThey share one pile, so add the rates: 3 plus 5 makes 8 potatoes per minute.
Rates with the same units add directly. Two peelers acting together is one combined rate of 8 potatoes per minute.
5.NBT.B.5Analyze The UnitsDivide the remainder by the joint rate: 32 over 8 gives 4 minutes of shared peeling.
Dividing potatoes by potatoes-per-minute leaves minutes — the time to finish at the joint pace.
6.RP.A.3Analyze The UnitsChristen worked only that shared span: 5 per minute for 4 minutes is 20 potatoes.
Christen only worked during phase 2, so her share is her rate times the phase-2 duration — nothing more, nothing less.
5.NBT.B.5Identify SubproblemsSplit the story into two phases — Homer alone, then both together. Subtract what Homer peeled alone, add the rates for the joint phase, and Christen's 4 minutes at 5/minute give 20 potatoes, answer (A).