AMC 8 · 2006 · #13
Grade 6 rate-ratioPick an answer.
AMC 8 2006 problem © Mathematical Association of America (MAA AMC). Reproduced for educational use.
This is a textbook rate/distance/time problem, so Tool #8 (Analyze Units) is the natural primary. Speeds are in mph and times are in minutes — convert minutes to hours so that speed × time gives miles cleanly. Tool #1 (Draw a Diagram) turns the word problem into a 62-mile segment with Cassie and Brian as arrows pointing at each other; once drawn, the head-start distance and the closing speed are easy to read off. We do not reach for Tool #13 (Algebra) because the picture plus unit-tracking gives the answer in three short steps.
Draw the 62-mile route with Cassie and Brian as arrows facing each other; she starts 30 minutes earlier.
Drawing the two riders with arrows toward each other makes the "closing the gap" idea visible — a Grade 4 multi-step word-problem move.
4.OA.A.3Draw A DiagramChange the 30-minute head start into hour, then multiply by her speed: Cassie covers 6 miles before Brian starts.
Grade 5 unit conversion: minutes to hours, then the "hr" units cancel so the answer comes out in miles, exactly what the problem needs.
5.MD.A.1Analyze The UnitsSubtract the 6-mile lead so 62 - 6 = 56 miles remain, and riding toward each other they close at 12 + 16 = 28 mph.
Two riders heading toward each other close the gap at the sum of their speeds — like two arrows squeezing inward on the diagram.
4.OA.A.3Analyze The UnitsDivide 56 by 28 to get 2 hours after Brian's 9 : 00 AM start, so they meet at 11 : 00 AM.
Grade 6 rate reasoning: time = distance ÷ rate. The miles cancel and hours pop out, which is exactly what the clock-time question wants.
6.RP.A.3Analyze The UnitsWhen two travelers move toward each other, peel off any head-start distance first, then divide the remaining gap by the sum of their speeds — the answer falls out in one step.